Write a function that returns how many decimal digits n is written with, counting 0 as one digit and never counting the minus sign.

• n is any int, anywhere from INT_MIN to INT_MAX. Return the number of decimal digits needed to write it.
• The sign is not a digit. -42 is written with two digits, exactly like 42.
• 0 is written with one digit, so digit_count(0) returns 1. A loop that tests the value before counting anything returns 0 here instead. Count the first digit before you look at what is left.
• Repeated division by 10 works on a negative n as it stands. Integer division in C truncates toward zero, so -42 / 10 is -4, then -4 / 10 is 0, which is two steps for two digits.
• Do not turn a negative n positive first. -INT_MIN is 2147483648, one past the top of the int range, and signed overflow is undefined behavior: the standard says nothing about the result and the compiler is free to keep the value negative or wrap it. Count n where it is, or widen it to a long before any negation.
• digit_count(INT_MIN) returns 10 and digit_count(INT_MAX) returns 10. Both numbers are written with ten digits.
• The tests print your return value with %d followed by a newline.

Write a function that returns how many decimal digits n is written with, counting 0 as one digit and never counting the minus sign.

• n is any int, anywhere from INT_MIN to INT_MAX. Return the number of decimal digits needed to write it.
• The sign is not a digit. -42 is written with two digits, exactly like 42.
• 0 is written with one digit, so digit_count(0) returns 1. A loop that tests the value before counting anything returns 0 here instead. Count the first digit before you look at what is left.
• Repeated division by 10 works on a negative n as it stands. Integer division in C truncates toward zero, so -42 / 10 is -4, then -4 / 10 is 0, which is two steps for two digits.
• Do not turn a negative n positive first. -INT_MIN is 2147483648, one past the top of the int range, and signed overflow is undefined behavior: the standard says nothing about the result and the compiler is free to keep the value negative or wrap it. Count n where it is, or widen it to a long before any negation.
• digit_count(INT_MIN) returns 10 and digit_count(INT_MAX) returns 10. Both numbers are written with ten digits.
• The tests print your return value with %d followed by a newline.